Hello 1¶
Solution to Hello 1
(defun hello (msg)
(format t "Hello, ~A!" msg))Remove 1¶
Solution 1¶
Solution to Remove 1
Remove doesn’t change the original list. It just returns a new list with that element removed.
We can use setf and bind the returned list back to the original variable/name:
(setf lst (remove 'c lst))This is somewhat similar to Go’s append() (and a few other languages as well), which always returns the new collection, to which we more often than not reassign to the same reference:
package main
import "fmt"
func main() {
nums := []int8{1, 2, 3}
nums = append(nums, 4)
fmt.Printf("%#v", nums)
//=> []int8{1, 2, 3, 4}
}However, if we are striving to work in a functional functional style and treat data structures as immutable, then we should avoid reassigning.